ch18-p060 - 60. The surface area of the ball is A = 4 R 2 =...

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60. The surface area of the ball is 22 3 2 4 4 (0.020 m) 5.03 10 m . AR ππ == = × Using Eq. 18-37 with 35 273 308 K i T =+ = and 47 273 320 K f T = , the power required to maintain the temperature is 44 8 2 4 3 2 4 4 ( ) (5.67 10 W/m K )(0.80)(5.03 10 m ) (320 K)
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