ch18-p062 - 62. (a) For each individual penguin, the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
where we have used / ra π = (from 2 ar = ) for the radius of the cylinder. For the huddled cylinder, the radius is / rN a ′ = (since 2 Na r = ), and the total surface area is 22 2 h Na AN a r h N a h N ah N a ππ =+ . Since the power radiated is proportional to the surface area, we have 21 2 / (2 )1 2 / hh rr PA Na h N a h Na NP NA Na h a h a ++ == = . With 1000 N = , 2 0.34 m a = and 1.1 m, h = the ratio is 2 2 1 2(1.1 m) /(1000 0.34 m ) 12 / 0.16 / 1 2(1.1 m) /(0.34 m )
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online