where we have used /raπ=(from 2ar=) for the radius of the cylinder. For the huddled cylinder, the radius is /rNa′ =(since 2Nar′=), and the total surface area is222hNaANarhNahNahNaππ′=+.Since the power radiated is proportional to the surface area, we have 212/(2)12/hhrrPANah N ahNaNPNANah aha++===.With 1000N=,20.34 ma=and 1.1 m,h=the ratio is 221 2(1.1 m)/(1000 0.34 m )12/0.16/1 2(1.1 m)/(0.34 m )
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