65. Let hbe the thickness of the slab and Abe its area. Then, the rate of heat flow through the slab is ()condHCkA TTPh−=wherekis the thermal conductivity of ice, THis the temperature of the water (0°C), and TCis the temperature of the air above the ice (–10°C). The heat leaving the water freezes it, the heat required to freeze mass mof water being Q = LFm, where LFis the heat of fusion for water. Differentiate with respect to time and recognize that dQ/dt = Pcondto obtaincond.FdmPLdt=Now, the mass of the ice is given by m = ρAh, where is the density of ice and his the thickness of the ice slab, so
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.