ch18-p065

# ch18-p065 - 65. Let h be the thickness of the slab and A be...

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65. Let h be the thickness of the slab and A be its area. Then, the rate of heat flow through the slab is () cond H C kA T T P h = where k is the thermal conductivity of ice, T H is the temperature of the water (0°C), and T C is the temperature of the air above the ice (–10°C). The heat leaving the water freezes it, the heat required to freeze mass m of water being Q = L F m , where L F is the heat of fusion for water. Differentiate with respect to time and recognize that dQ / dt = P cond to obtain cond . F dm PL dt = Now, the mass of the ice is given by m = ρ Ah , where is the density of ice and h is the thickness of the ice slab, so
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## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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