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65. Let
h
be the thickness of the slab and
A
be its area. Then, the rate of heat flow through
the slab is
()
cond
H
C
kA T
T
P
h
−
=
where
k
is the thermal conductivity of ice,
T
H
is the temperature of the water (0°C), and
T
C
is the temperature of the air above the ice (–10°C). The heat leaving the water freezes
it, the heat required to freeze mass
m
of water being
Q = L
F
m
, where
L
F
is the heat of
fusion for water. Differentiate with respect to time and recognize that
dQ
/
dt = P
cond
to
obtain
cond
.
F
dm
PL
dt
=
Now, the mass of the ice is given by
m =
ρ
Ah
, where
is the density of ice and
h
is the
thickness of the ice slab, so
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Conductivity, Heat

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