70. Let mw= 14 kg, mc= 3.6 kg, mm= 1.8 kg, Ti1= 180°C, Ti2= 16.0°C, and Tf= 18.0°C. The specific heat cmof the metal then satisfies ()()()210wwcmfimmfimcmcTTmcTT+−+−=which we solve for cm:()()()214kg 4.18kJ/kg K 16.0 C 18.0 C(3.6kg) 18.0 C 16.0 C
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.