(a) Path 2 involves more work than path 1 (note the triangle in the figure of area 12(4Vi)(pi/2) = piVi). With W2= 4piVi+ piVi= 5piVi, we obtain 225611.baiiQWUUpV=+−=+=(b) Path 3 starts at aand ends at bso that ΔU = Ub– Ua= 6p
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.