ch18-p087 - Thus, Q = Lm = (333 J/g)(1.00 g) = 333 J .

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87. We assume the ice is at 0°C to being with, so that the only heat needed for melting is that described by Eq. 18-16 (which requires information from Table 18-4).
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Unformatted text preview: Thus, Q = Lm = (333 J/g)(1.00 g) = 333 J ....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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