7. (a) In solving pV = nRTfor n, we first convert the temperature to the Kelvin scale: (40.0 273.15)K313.15 KT=+=. And we convert the volume to SI units: 1000 cm3= 1000×10–6m3. Now, according to the ideal gas law, ()()()56321.01 10 Pa 100010 m3.8810 mol.8.31J/mol K 313.15KpVnRT−
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