ch19-p008 - 8 The pressure p1 due to the first gas is p1 =...

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The fraction of P due to the second gas is then () 22 2 12 1 2 /0 . 5 0.2. /2 0 . 5 pn R T V n n R T Vn n == = = ++ + 8. The pressure p 1 due to the first gas is p 1 = n 1 RT / V , and the pressure p 2 due to the second gas is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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