ch19-p013 - 13. Suppose the gas expands from volume Vi to...

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Since the initial gauge pressure is 1.03 × 10 5 Pa, p i = 1.03 × 10 5 Pa + 1.013 × 10 5 Pa = 2.04 × 10 5 Pa. The final pressure is atmospheric pressure: p f = 1.013 × 10 5 Pa. Thus () ( ) 5 53 4 5 2.04 10 Pa 2.04 10 Pa 0.14m ln 2.00 10 J. 1.013 10 Pa W §· × = × ¨¸ × ©¹ During the constant pressure portion of the process the work done by the gas is W = p f ( V i V f ). The gas starts in a state with pressure p f , so this is the pressure throughout this portion of the process. We also note that the volume decreases from V f to V i . Now V f = p i V i / p f , so ( ) 55 3 4 1.013 10 Pa 2.04 10 Pa 0.14m 1.44 10 J. ii fi f i i f pV Wp V pp V p ¡¬ ­ ¢ ­ ¢ = . = . . × ­ ¢ ­ ­ ¢ £® =
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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