ch19-p014 - 14. (a) At the surface, the air volume is V1 =...

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() ( ) ( ) 53 3 (8.95 atm) 1.01 10 Pa/atm 11.44m 5.10 10 mol 8.31 J/mol K 243K pV n RT × Δ == = × . Thus, in order for the submarine to maintain the original air volume in the chamber, 3 5.10 10 mol × of air must be released. 14. (a) At the surface, the air volume is 23 3 1 (1.00 m) (4.00 m) 12.57 m 12.6 m VA h π = . (b) The temperature and pressure of the air inside the submarine at the surface are 1 20 C 293 K T =°= and 10 1.00 atm pp . On the other hand, at depth 80 m, h = we have 2 30 C 243 K T =− ° = and 32 20 5 1.00 atm 1.00 atm (1024 kg/m )(9.80 m/s )(80.0 m)
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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