ch19-p025 - 25(a Eq 19-24 gives K avg = 3(1.38 1023...

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25. (a) Eq. 19-24 gives () 23 21 avg 3 1.38 10 J/K (273K) 5.65 10 J . 2 K −− = × (b) For 373 K, T = the average translational kinetic energy is 21 avg 7.72 10 J . K (c) The unit mole may be thought of as a (large) collection: 6.02 × 10 23 molecules of ideal gas, in this case. Each molecule has energy specified in part (a), so the large
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