ch19-p031 - 31. (a) We use the ideal gas law pV = nRT =...

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The substitutions N = nN A and k = R / N A were made. Since 1 cm of mercury = 1333 Pa, the pressure is p = (10 –7 )(1333 Pa) = 1.333 × 10 –4 Pa. Thus, 4 16 3 10 3 23 1.333 10 Pa 3.27 10 molecules/m 3.27 10 molecules/cm . (1.38 10 J/K)(295K) Np Vk T × == = × × (b) The molecular diameter is d = 2.00 × 10 –10 m, so, according to Eq. 19-25, the mean
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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