ch19-p032 - 32. (a) We set up a ratio using Eq. 19-25: 2 d...

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32. (a) We set up a ratio using Eq. 19-25: () 2 2 2 2 2 N Ar Ar 2 NA r N 1/ 2 / . 2 / d dN V d V π §· λ == ¨¸ λ π ©¹ Therefore, we obtain 2 2 6 N Ar 6 r 27.5 10 cm 1.7. 9.9 10 cm d d λ × = λ× (b) Using Eq. 19-2 and the ideal gas law, we substitute N / V = N A n / V = N A p / RT into Eq. 19–25 and find 2 A . 2 RT dpN λ= π Comparing (for the same species of molecule) at two different pressures and temperatures, this leads to 22 1 11 2 . Tp λ § · = ¨ ¸ λ © ¹ With λ 1 = 9.9
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