ch19-p043 - N = 12 x 10 23 particles. Dividing the result...

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43. (a) The work is zero in this process since volume is kept fixed. (b) Since C V = 3 2 R for an ideal monatomic gas, then Eq. 19-39 gives Q = +374 J. (c) Δ E int = Q W = +374 J. (d) Two moles are equivalent to
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Unformatted text preview: N = 12 x 10 23 particles. Dividing the result of part (c) by N gives the average translational kinetic energy change per atom: 3.11 10 22 J....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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