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49. (a) From Table 193,
5
2
V
CR
=
and
7
2
p
=
. Thus, Eq. 1946 yields
()
3
7
3.00
8.31
40.0
3.49 10 J.
2
p
Qn
C T
§·
=Δ
=
=
×
¨¸
©¹
(b) Eq. 1945 leads to
3
int
5
3.00
8.31
40.0
2.49 10 J.
2
V
En
C
T
Δ=
Δ
=
=
×
(c) From either
W = Q –
Δ
E
int
or
W = p
Δ
T = nR
Δ
T
, we find
W
= 997 J.
(d) Eq. 1924 is written in more convenient form (for this problem) in Eq. 1938. Thus,
the increase in kinetic energy is
3
trans
avg
3
1.49 10 J.
2
KN
K
n
R
T
Δ
=
Δ
≈
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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