ch19-p052 - 52. (a) Using M = 32.0 g/mol from Table 19-1...

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52. (a) Using M = 32.0 g/mol from Table 19-1 and Eq. 19-3, we obtain sam 12.0 g 0.375 mol. 32.0 g/mol M n M == = (b) This is a constant pressure process with a diatomic gas, so we use Eq. 19-46 and Table 19-3. We note that a change of Kelvin temperature is numerically the same as a change of Celsius degrees. () 3 77 0.375 mol 8.31 J/mol K 100K 1.09 10 J. 22 p Qn CTn R T §· § · = Δ = = × ¨¸
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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