()()()3774.00mol 8.31J/mol K 60.0K6.98 10 J.22QnRT=Δ=⋅=×(b) The change in the internal energy is given by ΔEint= nCVΔT, where CVis the specific heat at constant volume. For a diatomic ideal gas 52VCR=, so ()()3int554.00mol 8.31J/mol.K 60.0K4.99 10 J.EnRTΔ=Δ==×(c) According to the first law of thermodynamics, ΔEint= Q – W, so 33 3int6.98 10 J4.99 10 J = 1.99 10 J.WQ E=−Δ =×−××(d) The change in the total translational kinetic energy is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.