ch19-p059 - processes (involving an ideal gas) the internal...

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59. The aim of this problem is to emphasize what it means for the internal energy to be a state function. Since path 1 and path 2 start and stop at the same places, then the internal energy change along path 1 is equal to that along path 2. Now, during isothermal
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Unformatted text preview: processes (involving an ideal gas) the internal energy change is zero, so the only step in path 1 that we need to examine is step 2. Eq. 19-28 then immediately yields 20 J as the answer for the internal energy change....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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