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Unformatted text preview: 60. Let pi, Vi, and Ti represent the pressure, volume, and temperature of the initial state of
the gas, and let pf, Vf, and Tf be the pressure, volume, and temperature of the final state.
Since the process is adiabatic piVi = p f V f . Combining with ideal-gas law, pV = NkT ,
piVi γ = pi (Ti / pi )γ = pi1−γ Ti γ = constant pi1−γ Ti γ = p1f−γ T fγ With γ = 4 / 3 which gives (1 − γ ) / γ = −1/ 4 , the temperature at the end of the adiabatic
1−γ Tf = pi
pf γ Ti = 5.00 atm
1.00 atm −1/ 4 (278 K) = 186 K = −87°C . ...
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- Spring '08