ch19-p071 - = avg v = p d 2 k 16 R MT . Therefore, with p =...

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71. This is very similar to Sample Problem 19-4 (and we use similar notation here) except for the use of Eq. 19-31 for v avg (whereas in that Sample Problem, its value was just assumed). Thus, f = speed distance
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Unformatted text preview: = avg v = p d 2 k 16 R MT . Therefore, with p = 2.02 10 3 Pa, d = 290 10 12 m and M = 0.032 kg/mol (see Table 19-1), we obtain f = 7.03 10 9 s 1 ....
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