ch19-p074 - T 3 = T 1 which means T = 0 for this process....

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74. (a) With P 1 = (20.0)(1.01 × 10 5 Pa) and V 1 = 0.0015 m 3 , the ideal gas law gives P 1 V 1 = nRT 1 ¡ T 1 = 121.54 K 122 K. (b) From the information in the problem, we deduce that T 2 = 3 T 1 = 365 K. (c) We also deduce that
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Unformatted text preview: T 3 = T 1 which means T = 0 for this process. Since this involves an ideal gas, this implies the change in internal energy is zero here....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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