ch19-p077 - 77(a The final pressure is pf = pVi 32 atm(1.0...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
(d) The final pressure is () 53 1.0L 32atm 3.2atm. 4.0L i fi f V pp V γ §· == = ¨¸ ©¹ (e) The final temperature is ( ) ( ) ( ) 3.2atm 4.0L 300K 120K 32atm 1.0L ff i f ii pVT T pV = . (f) The work done is ( ) ( ) ( ) int int 3 3 33 22 3 3.2atm 4.0L 1.01 10 Pa atm 10 m L 2 2.9 10 J . i i W Q E E nR T p V =− Δ = Δ= ªº × ¬¼ (g) If the gas is diatomic, then = 1.4, and the final pressure is 1.4 4.6atm i f V V = . (h) The final temperature is ( ) ( ) ( ) 4.6atm 4.0L 300K 170K i f T = . 77. (a) The final pressure is ( ) 8.0atm, f f p V = (b) For the isothermal process the final temperature of the gas is T f = T i = 300 K. (c) The work done is ( ) 3 3 ln ln 32atm 1.01 10 Pa atm 1.0 10 m ln 4.4 10 J. i VV Wn R T p V = × × For the adiabatic process
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

ch19-p077 - 77(a The final pressure is pf = pVi 32 atm(1.0...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online