ch20-p005 - 5. (a) Since the gas is ideal, its pressure p...

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5. (a) Since the gas is ideal, its pressure p is given in terms of the number of moles n , the volume V , and the temperature T by p = nRT / V . The work done by the gas during the isothermal expansion is 22 11 2 1 ln . == = ³³ VV dV V Wp d V n R T n R T We substitute V 2 = 2.00 V 1 to obtain () ( ) ( ) 3 = ln2.00 = 4.00 mol 8.31 J/mol K 400 K ln2.00 = 9.22 10 J. Wn R T ⋅× (b) Since the expansion is isothermal, the change in entropy is given by 1 ST d Q Q T Δ= = ³ , where Q is the heat absorbed. According to the first law of thermodynamics,
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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