5. (a) Since the gas is ideal, its pressure pis given in terms of the number of moles n, the volume V, and the temperature Tby p = nRT/V. The work done by the gas during the isothermal expansion is 221121ln.===³³VVdVVWpdVnRTnRTWe substitute V2= 2.00V1to obtain ()()()3=ln2.00 = 4.00 mol 8.31 J/mol K400 K ln2.00 = 9.22 10 J.WnRT⋅×(b) Since the expansion is isothermal, the change in entropy is given by 1STdQQTΔ==³,whereQis the heat absorbed. According to the first law of thermodynamics,
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.