ch20-p010 - 3 , we are able to deduce that V i = 0.40 m 3 ....

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10. We concentrate on the first term of Eq. 20-4 (the second term is zero because the final and initial temperatures are the same, and because ln(1) = 0). Thus, the entropy change is Δ S = nR ln( V f / V i ) . Noting that Δ S = 0 at V f = 0.40 m
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Unformatted text preview: 3 , we are able to deduce that V i = 0.40 m 3 . We now examine the point in the graph where S = 32 J/K and V f = 1.2 m 3 ; the above expression can now be used to solve for the number of moles. We obtain n = 3.5 mol....
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