ch20-p016 - 16. (a) Work is done only for the ab portion of...

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16. (a) Work is done only for the ab portion of the process. This portion is at constant pressure, so the work done by the gas is 0 0 4 00 0 0 0 (4.00 1.00 ) 3.00 3.00 V V W Wp d V p VV p V pV ==− = ¡ = ³ (b) We use the first law: Δ E int = Q W . Since the process is at constant volume, the work done by the gas is zero and E int = Q . The energy Q absorbed by the gas as heat is Q = nC V Δ T , where C V is the molar specific heat at constant volume and Δ T is the change in temperature. Since the gas is a monatomic ideal gas, 3 / 2 V CR = . Use the ideal gas law to find that the initial temperature is 4 bb b p Vp V T nR nR == and that the final temperature is 0 0 (2 )(4 ) 8 cc c p V T nR nR nR = . Thus, 84 3 6 . 0 0 . 2 Qn R p V nR nR §· ¨¸ ©¹ The change in the internal energy is
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