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L
H
333 K
=1
= 0.107.
373 K
T
T
ε
−−
We recall that a Watt is Joulepersecond. Thus, the (net) work done by the cycle per unit
time is the given value 500 J/s. Therefore, by Eq. 2011, we obtain the heat input per unit
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Work, Heat

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