ch20-p041 - 41. The efficiency of the engine is defined by...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
The work done by the engine is used to drive the refrigerator, so W is the same for the two. Solve the engine equation for W and substitute the resulting expression into the refrigerator equation. The engine equation yields W = ( T 1 T 2 ) Q 1 / T 1 and the substitution yields ( ) 33 1 4 34 1 12 =1 = 1 . QQ T T TT W QTT −− Solving for Q 3 / Q 1 , we obtain () 21 41 2 1 2 13 4 1 3 4 1 4 3 1 1. 1 TT QT T T T T T T T T T T §· § · =+ = = ¨¸ ¨ ¸ ©¹ © ¹ With T 1 = 400 K, T 2 = 150 K, T 3 = 325 K, and T 4 = 225 K, the ratio becomes Q 3 / Q 1 =2.03. 41. The efficiency of the engine is defined by
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online