ch20-p062 - 62(a Eq 20-14 gives K = 560/150 = 3.73(b Energy...

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62. (a) Eq. 20-14 gives K = 560/150 = 3.73. (b) Energy conservation requires the exhaust heat to be 560 + 150 = 710 J.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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