ch20-p065 - the situation described by the problem has...

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65. (a) Eq. 20-2 gives the entropy change for each reservoir (each of which, by definition, is able to maintain constant temperature conditions within itself). The net entropy change is therefore Δ S = + | Q | 273 + 24 + | Q | 273 + 130 = 4.45 J/K where we set | Q | = 5030 J. (b) We have assumed that the conductive heat flow in the rod is “steady-state”; that is,
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Unformatted text preview: the situation described by the problem has existed and will exist for long times. Thus there are no entropy change terms included in the calculation for elements of the rod itself....
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