()
(
)
22
2
2
00

1



1
sin 45
44


2
y
qQ
qq
Q
F
aa
q
a
πε
⎛⎞
⎜⎟
=°
−
=
−
⎝⎠
which (if we demand
F
2
y
= 0) leads to
/1
/
2
2
Qq
=−
. The result is inconsistent with
that obtained in part (a). Thus, we are unable to construct an equilibrium configuration
with this geometry, where the only forces present are given by Eq. 211.
8. For ease of presentation (of the computations below) we assume
Q
> 0 and
q
< 0
(although the final result does not depend on this particular choice).
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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