17. (a) The distance between q1and q2is ()()22221221210.020 m 0.035 m0.015 m 0.005 m0.056 m.rxxyy=−+−=−−+−=The magnitude of the force exerted by q1on q2is ( ) ( )922661221128.99 10 N m C3.0 10 C4.0 10 C||35 N.(0.056 m)qqFkr−−×⋅××===(b) The vector GF21is directed towards q1and makes an angle θwith the +xaxis, where 11211.5 cm 0.5 cmtantan10.310 .2.0 cm 3.5 cmyyxx⎛⎞−−=−°≈−°⎜⎟−⎝⎠(c) Let the third charge be located at (x3, y3), a distance rfrom q2. We note that q1, q2and q3must be collinear; otherwise, an equilibrium position for any one of them would be impossible to find. Furthermore, we cannot place q3on the same side of q2where we also find q1, since in that region both forces (exerted on q2by q3and q1) would be in the same
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.