ch21-p032

# ch21-p032 - particle 3 and particle 2 is L x . Both...

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with the values of the charges (stated in the problem) plugged in. Finding the value of x which minimizes this expression leads to x = ¼ L . Thus, x = 2.00 cm. (b) Substituting x = ¼ L back into the expression for the net force magnitude and using the standard value for e leads to F net = 9.21 × 10 24 N. 32. (a) Let x be the distance between particle 1 and particle 3. Thus, the distance between
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Unformatted text preview: particle 3 and particle 2 is L x . Both particles exert leftward forces on q 3 (so long as it is on the line between them), so the magnitude of the net force on q 3 is F net = | F 1 3 | + | F 2 3 | = | q 1 q 3 | 4 o x 2 + | q 2 q 3 | 4 o ( L x ) 2 = e 2 o 1 x 2 + 27 ( L x ) 2...
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## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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