Ch21-p037 - (a 1 H has 1 proton 1 electron and 0 neutrons and 9 Be has 4 protons 4 electrons and 9 – 4 = 5 neutrons so X has 1 4 = 5 protons 1 4

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(c) 15 N has 7 protons, 7 electrons, and 15 – 7 = 8 neutrons; 1 H has 1 proton, 1 electron, and 0 neutrons; and 4 He has 2 protons, 2 electrons, and 4 – 2 = 2 neutrons; so X has 7 + 1 – 2 = 6 protons, 6 electrons, and 8 + 0 – 2 = 6 neutrons. It must be carbon with a molar mass of 6 + 6 = 12: 12 C. 37. None of the reactions given include a beta decay, so the number of protons, the number of neutrons, and the number of electrons are each conserved. Atomic numbers (numbers of protons and numbers of electrons) and molar masses (combined numbers of protons and neutrons) can be found in Appendix F of the text.
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Unformatted text preview: (a) 1 H has 1 proton, 1 electron, and 0 neutrons and 9 Be has 4 protons, 4 electrons, and 9 – 4 = 5 neutrons, so X has 1 + 4 = 5 protons, 1 + 4 = 5 electrons, and 0 + 5 – 1 = 4 neutrons. One of the neutrons is freed in the reaction. X must be boron with a molar mass of 5 + 4 = 9 g/mol: 9 B. (b) 12 C has 6 protons, 6 electrons, and 12 – 6 = 6 neutrons and 1 H has 1 proton, 1 electron, and 0 neutrons, so X has 6 + 1 = 7 protons, 6 + 1 = 7 electrons, and 6 + 0 = 6 neutrons. It must be nitrogen with a molar mass of 7 + 6 = 13 g/mol: 13 N....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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