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42. Let
q
1
be the charge of one part and
q
2
that of the other part; thus,
q
1
+
q
2
=
Q
= 6.0
µ
C.
The repulsive force between them is given by Coulomb’s law:
12
1
1
22
00
()
44
qq
q Q q
F
rr
πε
−
==
.
If we maximize this expression by taking the derivative with respect to
q
1
and setting
equal to zero, we find
q
1
=
Q
/2 , which might have been anticipated (based on symmetry
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Charge, Force

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