42. Let q1be the charge of one part and q2that of the other part; thus, q1 + q2 = Q= 6.0 µC. The repulsive force between them is given by Coulomb’s law: 12112200()44qqq Q qFrrπε−==. If we maximize this expression by taking the derivative with respect to q1 and setting equal to zero, we find q1 = Q/2 , which might have been anticipated (based on symmetry
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.