ch21-p046 - 46. (a) Since qA = 2.00 nC and qC = +8.00 nC...

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92 2 9 9 6 22 0 || | (8.99 10 N m C )( 3.00 10 C)( 4.00 10 C) | | | 2.70 10 N. 4 (0.200 m) AC AC qq F d πε −− × −× == = × G (c) We also obtain 2 9 9 6 0 | (8.99 10 N m C )( 4.00 10 C)( 4.00 10 C) | | | 3.60 10 N. 4 (0.200 m) BC BC F d × = × G 46. (a) Since q A = –2.00 nC and q C = +8.00 nC Eq. 21-4 leads to 2 9 9 6 0 | (8.99 10 N m C )( 2.00 10 C)(8.00 10 C) | | | 3.60 10 N. 4 (0.200 m) AC F d ×⋅ × × = × G (b) After making contact with each other, both A and B have a charge of ( ) 2.00 4.00 nC 3.00 nC. AB ⎛⎞
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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