algebraically solve for the half-height points (this involves the use of the quadratic formula). The results are 121110.15 and 10.85.22αα⎛⎞=−≈=+≈⎜⎟⎝⎠Thus, the smaller value of αis 10.15=, (c) and the larger value of is 20.85=. 51. The two charges are q= Q(where is a pure number presumably less than 1 and greater than zero) and Q– q= (1 – )Q. Thus, Eq. 21-4 gives FQQdQd=−=−1411402202ππεbg bgchbg.The graph below, of Fversus , has been scaled so that the maximum is 1. In actuality,
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.