This preview shows page 1. Sign up to view the full content.
59. (a) Charge
Q
1
= +80
×
10
–9
C is on the
y
axis at
y
= 0.003 m, and charge
9
2
80 10 C
Q
−
=+ ×
is on the
y
axis at
y
= –0.003 m. The force on particle 3 (which has a
charge of
q
= +18
×
10
–9
C) is due to the vector sum of the repulsive forces from
Q
1
and
Q
2
. In symbols,
31
32
3
,
FF
F
+=
GG
G
where
3
2
22

,
.
qq
q
q
Fk
rr
==
Using the Pythagorean theorem, we have
r
31
=
r
32
= 0.005 m. In magnitudeangle
notation (particularly convenient if one uses a vectorcapable calculator in polar mode),
the indicated vector addition becomes
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '08
 Any
 Physics, Charge, Force

Click to edit the document details