Ch21-p066 - 66 Let the two charges be q1 and q2 Then q1 q2 = Q = 5.0 105 C We use Eq 21-1(8.99 10 1.0N = 9 N m 2 C2 q1q2 2.0m 2 We substitute q2 =

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66. Let the two charges be q 1 and q 2 . Then q 1 + q 2 = Q = 5.0 × 10 –5 C. We use Eq. 21-1: ( ) () 92 2 12 2 8.99 10 N m C 1.0N . 2.0m qq ×⋅ = We substitute q 2 = Q q 1 and solve for q 1 using the quadratic formula. The two roots obtained are the values of
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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