ch23-p053 - 53. We use E (r ) = qenc 1 = 2 4 0 r 4 0 r 2 r...

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53. We use 2 enc 22 0 00 1 () ()4 44 r q Er r rd r rr ρ εε == π ππ to solve for ( r ) and obtain ε . r r d dr rEr
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