ch23-p061 - 61. (a) At x = 0.040 m, the net field has a...

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61. (a) At x = 0.040 m, the net field has a rightward (+ x ) contribution (computed using Eq. 23-13) from the charge lying between x = –0.050 m and x = 0.040 m, and a leftward (– x ) contribution (again computed using Eq. 23-13) from the charge in the region from 0.040 m x = to x = 0.050 m. Thus, since σ = q / A = ρ V / A = x in this situation, we have 93 12 2 2 00 (0.090m)
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