ch24-p045 - . 45. (a) Let = 015 m be the length of the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
energy when q 3 is at A and U B is the potential energy when q 3 is at B , then the work done in moving the charge from B to A is W = U A – U B = q 3 ( V A – V B ) = (3.0 × 10 –6 C)(6.0 × 10 4 V + 7.8 × 10 5 V) = 2.5 J. (d) The work done by the external agent is positive, so the energy of the three-charge system increases. (e) and (f) The electrostatic force is conservative, so the work is the same no matter which path is used. 45. (a) Let A = 015 . m be the length of the rectangle and w = 0.050 m be its width. Charge q 1 is a distance A from point A and charge q 2 is a distance w , so the electric potential at A is 66 92 2 12 0 4 1 5.0 10 C 2.0 10 C (8.99 10 N m / C ) 4 0.15m 0.050 m 6.0 10 V. A qq V w ε −− ⎛⎞ −× × =+ =
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online