20124eqmvrπε=where m= 9.11×10−31 kg, e= 1.60×10−19 C, q= 10000e, and r= 0.010 m. This yields v= 22490 m/s 42.2 10 m/s≈×. 49. The escape speedmay be calculated from the requirement that the initial kinetic
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.