Ch24-p068 - R 68(a We use Eq 24-18 to find the potential Vwall V = Edr or r R r 0 V = r 2 0 V = R2 r 2 4 0 Consequently V =(R2 r2/40(b The value at

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
68. (a) We use Eq. 24-18 to find the potential: wall R r VV E d r −= , or () 22 00 0 . 24 R r r R r ρρ εε ⎛⎞ ⇒−= ⎜⎟ ⎝⎠ Consequently, V = ρ ( R 2 r 2 )/4 ε 0 . (b) The value at r = 0 is V center 3 Cm CVm
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online