ch24-p111 - 111 We denote q = 25 109 C y = 0.6 m x = 0.8 m...

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111. We denote q = 25 × 10 –9 C, y = 0.6 m, x = 0.8 m, with V = the net potential (assuming V 0 as r ). Then, ( ) ( ) 00 11 , 44 AB qq VV yx xy πε =+ leads to 0 92 2 9 222 1 1 4 2(8.99 10 N m C )(25 10 C) 187 V . 0.80 m 0.60 m
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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