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VV
a
xa y
a
net
=+
−+
F
H
G
G
I
K
J
J
−
++
F
H
G
G
I
K
J
J
F
H
G
G
I
K
J
J
=
F
H
G
I
K
J
2
4
0
2
2
2
2
0
2
2
2
2
λ
2π
λ
π
0
εε
ln
ln
ln
b
g
b
g
b
g
bg
where we have set the potential along the
z
axis equal to zero (
V
o
= 0) in the last step
(which we are free to do). This is the expression used to obtain the equipotentials shown
next. The center dot in the figure is the intersection of the
z
axis with the
xy
plane, and the
dots on either side are the intersections of the wires with the plane.
117. From the previous chapter, we know that the radial field due to an infinite line
source is
E
r
=
λ
2π
0
ε
which integrates, using Eq. 2418, to obtain
dr
r
V
r
r
if
r
r
f
f
i
i
f
F
H
G
I
K
J
z
λ
2π
λ
2π
00
ln
.
The subscripts
i
and
f
are somewhat arbitrary designations, and we let
V
i
= V
be the
potential of some point
P
at a distance
r
i
= r
from the wire and
V
f
= V
o
be the potential
along some reference axis (which will be the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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