ch24-p118

# ch24-p118 - r ≤ R This agrees with the Rutherford field...

This preview shows page 1. Sign up to view the full content.

118. The electric field (along the radial axis) is the (negative of the) derivative of the voltage with respect to r . There are no other components of E in this case, so (noting that the derivative of a constant is zero) we conclude that the magnitude of the field is E = dV dr = Ze 4 πε o d r 1 dr + 0 + 1 2 R 3 d r 2 dr = Ze 4 πε o 1 r 2 r R 3 for
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: r ≤ R . This agrees with the Rutherford field expression shown in exercise 37 (in the textbook). We note that he has designed his voltage expression to be zero at r = R . Since the zero point for the voltage of this system (in an otherwise empty space) is arbitrary, then choosing V = 0 at r = R is certainly permissible....
View Full Document

## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online