ch25-p044 - 44. Each capacitor has 12.0 V across it, so Eq....

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C 2 = ε 0 A d = 2.21 × 10 11 F , and from Eq. 25-27, C 1 = κε 0 A d = 6.64 × 10 11 F . This leads to q 1 = C 1 V 1 = 8.00 × 10 10 C and q 2 = C 2 V 2 = 2.66 × 10 10 C. The addition of these gives the desired result: q tot = 1.06 × 10 9 C. Alternatively, the circuit could be
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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