51. (a) The electric field in the region between the plates is given by E = V/d, where Vis the potential difference between the plates and dis the plate separation. The capacitance is given by C= κε0A/d, where Ais the plate area and κis the dielectric constant, so 0/dAC=and EVCA==×××=×−−−0121242450100 1054 885 10100 1010 10VFFmmVmbgchchch..(b) The free charge on the plates is qf= CV= (100 ×10–12F)(50 V) = 5.0 ×10–9C. (c) The electric field is produced by both the free and induced charge. Since the field of a large uniform layer of charge is q/2ε0A, the field between the plates is EqAqAqAqAffii=+−−22220000εεεε, where the first term is due to the positive free charge on one plate, the second is due to
This is the end of the preview. Sign up
access the rest of the document.