ch25-p059 - 59. Initially, the total equivalent capacitance...

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59. Initially, the total equivalent capacitance is C 12 = [ ( C 1 ) 1 + ( C 2 ) 1 ] 1 = 3.0 µ F, and the charge on the positive plate of each one is (3.0 µ F)(10 V) = 30 µ C. Next, the capacitor (call is C 1 ) is squeezed as described in the problem, with the effect that the new value of C 1 is 12 µ F (see Eq. 25-9). The new total equivalent capacitance then becomes C 12 = [ ( C 1 ) 1 + ( C 2 ) 1 ] 1 = 4.0 µ F, and the new charge on the positive plate of each one is (4.0
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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