ch25-p078 - 1 2 CV 2 . The total energy stored by the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
78. One way to approach this is to note that – since they are identical – the voltage is evenly divided between them. That is, the voltage across each capacitor is V = (10/ n ) volt. With C = 2.0 × 10 6 F, the electric energy stored by each capacitor is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 2 CV 2 . The total energy stored by the capacitors is n times that value, and the problem requires the total be equal to 25 10 6 J. Thus, n 2 (2.0 10 6 ) 10 n 2 = 25 10 6 leads to n = 4....
View Full Document

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online